-10a^2=-200

Solution for -10a^2=-200 equation:

-10a^2=-200

We move all terms to the left:

-10a^2-(-200)=0

We add all the numbers together, and all the variables

-10a^2+200=0

a = -10; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-10)·200
Δ = 8000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8000}=\sqrt{1600*5}=\sqrt{1600}*\sqrt{5}=40\sqrt{5}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{5}}{2*-10}=\frac{0-40\sqrt{5}}{-20}
=-\frac{40\sqrt{5}}{-20}
=-\frac{2\sqrt{5}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{5}}{2*-10}=\frac{0+40\sqrt{5}}{-20}
=\frac{40\sqrt{5}}{-20}
=\frac{2\sqrt{5}}{-1}
$